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of parts for my project quad for a while and I am now considering suspension It will be ridden almost exclusively in the dunes with very rare moto outings I have taken a look at the new Pro G Series shocks from Works and my first impression is pretty good However I have not ridden them so I have no idea how they will perform Has anyone experienced them yet I hope
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*The iron man of MSU's lineup, senior G Barry Stewart is working over 33 minutes per-game. That's still down from the 35.7 minutes he put in each game as a ...
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How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from?
Q. How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from? How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from? How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from? 22.4 Celsius to 94.6 Celsius? The specific heat of aluminum is 0.897 J/g (K). Note that a temperature change of 1 degree celsius isthe same as 1 Kelvin because the sizes of the degree divisions on both scales are equal. Please explain the steps because I'm lost.
Asked by Luv2singnbling - Mon Sep 10 22:10:46 2007 - - 1 Answers - 0 Comments
A. ok, the formula to use is q=mc T T = 94.6 - 22.4 = 72.2 q = (55 g)(0.897 J/gK)(72.2K) q = 356 J
Answered by ChemistryMom - Mon Sep 10 22:22:15 2007
Q. How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from? How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from? How much energy as heat must be transferred to raise the temperature of a 55 g sample of aluminum foil from? 22.4 Celsius to 94.6 Celsius? The specific heat of aluminum is 0.897 J/g (K). Note that a temperature change of 1 degree celsius isthe same as 1 Kelvin because the sizes of the degree divisions on both scales are equal. Please explain the steps because I'm lost.
Asked by Luv2singnbling - Mon Sep 10 22:10:46 2007 - - 1 Answers - 0 Comments
A. ok, the formula to use is q=mc T T = 94.6 - 22.4 = 72.2 q = (55 g)(0.897 J/gK)(72.2K) q = 356 J
Answered by ChemistryMom - Mon Sep 10 22:22:15 2007
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